Been trying to get some numbers together to ascertain the force when the blade hits the log, so need some maths boys to work it out, here are the details, max drop blade to base = 1.5Mt weight of cylinder 60Kg, now this is the bit of the calk that I cannot get my head around, penetration of blade into log? if I put in 0.001 Mt then assuming a 300mm log I get 7202Kg if the log is softer and it penetrates 0.01Mt then I get 720Kg, but should I increase the drop by 90mm to compensate? sorry can someone please explain, Rick
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Ex banger racer now off road maniac 
Lokka on the front with manual hubs
Diff lock on rear
3 inch SS straight through exhaust
Manly winch bumper with 13000 lb winch
10 spike ground anchor, with multiple straps and blocks
Super strong body cills capped with scaffold pole
20% stronger springs all round
aggressive off road tyres on wheels so just swap.
Aim to get stuck and be completely self sufficient in extraction, love getting muddy, 2ft deep is good but rare.
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